1. Strength of Solutions
The amount of solute dissolved per unit solution or solvent is called Strength of solution. There are various methods of measuring strength of a solution. :
1. Mass Percentage (%w/w):
“It represents mass of a component present in 100 g of solution”
Mass% of a component = Mass of the component in the sol. *100/Total Mass of sol
2. Volume percentage (%v/v):
2. Volume percentage (%v/v):
“It represents volume of a component in 100 mL of solution”
Vol. % of a component = Vol. of component ×100 /Total vol. of solution
3. Mass by volume percentage (%w/v):
“It represents mass of solute in grams present in 100 mL of
solution”
Mass by vol. percent = Mass of solute in gram *100/Vol. of sol.in ml
4. Parts per Million (ppm):
"Concentration in parts per million can be expressed as mass
to mass, volume to volume and mass to volume."
Parts per Million = (No. of parts of the component/Total no. of all the components of sol.)*106
5. Mole Fraction (x) :
“It represents the moles of a solute present in one mole of solution”
5. Mole Fraction (x) :
“It represents the moles of a solute present in one mole of solution”
Mole fraction=No. of moles of the component/Total no. of moles all the components
For example, in a binary mixture, if the number of moles of A and B are nA and nB respectively, the mole fraction of A will be
xA =nA/nA + nB
For example, in a binary mixture, if the number of moles of A and B are nA and nB respectively, the mole fraction of A will be
xA =nA/nA + nB
6. Molarity, M:
“It represents moles of solute present in 1 L of solution”
Molarity, M = Moles of solute / Vol. of sol. in L
Units of Molarity are mol/L also represented by ‘M’ or ‘Molar’.
“Density of a solution = mass of the solution per unit volume”
Density, d = m / V
7. Molality, m:
“It represents moles of solute present per kg of solvent”
Molality, m = Moles of solute/Mass of solvent in kg
Units of molality are mol/kg which is also represented by ‘m’ or ‘molal’
8. Normality, N
It represents no. of equivalents of solute present in 1 L of solution.
Normality, N = No. of Equivalents of solute/Vol. of sol. in L
No. of equivalents, eq = Weight/Equivalent weight (W / E)
E=M/z(z is the valency factor)
SOME IMPORTANT RELATIONSHIPS
Dilution Law
M1V1 = M2V2 and N1V1 = N2V2
Molarity and Normality
Normality = z × Molarity]
IMPORTANT :
Mass %, ppm, mole fraction and molality are independent of temperature, whereas molarity & normality are a function of temperature. This is because volume depends on temperature and the mass does not.